SOLUTION: 3x2 + 7x > -12

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Question 610240: 3x2 + 7x > -12
Answer by jsmallt9(3758) About Me  (Show Source):
You can put this solution on YOUR website!
3x%5E2+%2B+7x+%3E+-12
Like quadratic equations, you want one side to be zero and then factor the other side. Adding 12 to each side we get:
3x%5E2+%2B+7x+%2B+12+%3E+0
Then we factor. But this won't factor!

We can use the Quadratic Formula to tell us something helpful:
x+=+%28-%287%29+%2B-+sqrt%28%287%29%5E2+-+4%283%29%2812%29%29%29%2F2%283%29
Simplifying:
x+=+%28-%287%29+%2B-+sqrt%2849+-+4%283%29%2812%29%29%29%2F2%283%29
x+=+%28-%287%29+%2B-+sqrt%2849+-+144%29%29%2F2%283%29
x+=+%28-%287%29+%2B-+sqrt%28-95%29%29%2F2%283%29
At this point, with the negative in the square root, we can stop. The formula is trying to tell us x value(s) that make 3x%5E2%2B7x%2B12 equal to zero. Since we cannot have a negative inside a square root, this tells us that 3x%5E2%2B7x%2B12 is never equal to zero.

If 3x%5E2%2B7x%2B12 is never equal to zero, it must always be positive or always be negative. We can quickly see that when x = 0, 3x%5E2%2B7x%2B12 will be a 12. 12 is positive. Since 3x%5E2%2B7x%2B12 is always positive or negative and since we have found a case where it is positive, 3x%5E2%2B7x%2B12 must always be positive. So the solution to
3x%5E2+%2B+7x+%2B+12+%3E+0
which says that 3x%5E2+%2B+7x+%2B+12 is positive, is:
All real numbers. In other words, no matter what number you use for x, 3x%5E2+%2B+7x+%2B+12 will work out to be positive.