SOLUTION: A soccer ball is kicked vertically at 33 ft/sec. How high does it go? Use the formula {{{ H(t) = -16t^2+vt+s }}}

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Question 609643: A soccer ball is kicked vertically at 33 ft/sec. How high does it go? Use the formula
++H%28t%29+=+-16t%5E2%2Bvt%2Bs+
Answer by Alan3354(69443) About Me  (Show Source):
You can put this solution on YOUR website!
A soccer ball is kicked vertically at 33 ft/sec. How high does it go? Use the formula
++H%28t%29+=+-16t%5E2%2Bvt%2Bs+
s = 0
++H%28t%29+=+-16t%5E2+%2B+33t+
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Find the times of the 2 zeroes, 1 when launched, the 2nd on impact.
The time at apogee is the average of the 2 times.
++H%28t%29+=+-16t%5E2+%2B+33t+=+0+
t = 0, t = 33/16 seconds
t of max = 33/32 seconds
apogee = H(33/32)