SOLUTION: Complete the square and write the equation in standard form.Then give the center and radius of the circle. x^2+y^2+18x+8y=-93
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-> SOLUTION: Complete the square and write the equation in standard form.Then give the center and radius of the circle. x^2+y^2+18x+8y=-93
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Question 608352
:
Complete the square and write the equation in standard form.Then give the center and radius of the circle. x^2+y^2+18x+8y=-93
Answer by
solver91311(24713)
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You can
put this solution on YOUR website!
Rearrange:
Divide the coefficient on the 1st degree
term by 2. Square the result. Add the square to both sides of the equation.
Divide the coefficient on the 1st degree
term by 2. Square the result. Add the square to both sides of the equation.
Factor the two perfect square trinomials in the LHS and collect terms in the RHS:
Rewrite for standard form:
A circle with center at
and radius
has an equation:
So you should be able to determine the center coordinates and radius by inspection.
John
My calculator said it, I believe it, that settles it
