SOLUTION: Hi, Can someone help me please? I am completely lost. 8x+x(x-2)=0 I need the solutions of x and the x intercepts of f(x)=8x+x(x-2) Thanks so much

Algebra ->  Quadratic Equations and Parabolas  -> Quadratic Equations Lessons  -> Quadratic Equation Lesson -> SOLUTION: Hi, Can someone help me please? I am completely lost. 8x+x(x-2)=0 I need the solutions of x and the x intercepts of f(x)=8x+x(x-2) Thanks so much      Log On


   



Question 607530: Hi,
Can someone help me please? I am completely lost.
8x+x(x-2)=0
I need the solutions of x
and the x intercepts of f(x)=8x+x(x-2)
Thanks so much

Found 2 solutions by alicealc, nerdybill:
Answer by alicealc(293) About Me  (Show Source):
You can put this solution on YOUR website!
8x%2Bx%28x-2%29=0
8x%2Bx%5E2+-+2x=0
x%5E2+%2B+6x+=+0
x*(x + 6) = 0
x = 0 or x + 6 = 0
x = 0 or x = -6

The x intercepts of f(x)=8x+x(x-2) can be found by substituting f(x) with 0.
It will result the same equation as above, so the x intercepts of f(x)=8x+x(x-2) is (0, 0) and (-6, 0)

Answer by nerdybill(7384) About Me  (Show Source):
You can put this solution on YOUR website!
8x+x(x-2)=0
factor out an x:
x(8+(x-2))=0
x(8+x-2)=0
x(x+6)=0
x = {0, -6}
.
Note:
the above are both
the solutions of x
AND
the x-intercepts of f(x)=8x+x(x-2))