SOLUTION: (8t-3)^2=0 (2x-1)^2=8 x^2-4x+4=49

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Question 60623This question is from textbook college algebra
: (8t-3)^2=0
(2x-1)^2=8
x^2-4x+4=49 This question is from textbook college algebra

Answer by checkley71(8403) About Me  (Show Source):
You can put this solution on YOUR website!
(8T-3)^2=0
64T^2-48T+9=0
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(2X-1)^2=8
4X^2-4X+1=8
4X^2-4X-7=0
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X^2-4X+4=49
X^2-4X+4-49=0
X62-4X-45=0