SOLUTION: 4x^3+3x^2=64x+48 I tried and ended up with x=16,-16, and -3/4. Is that correct?

Algebra ->  Quadratic Equations and Parabolas  -> Quadratic Equations Lessons  -> Quadratic Equation Lesson -> SOLUTION: 4x^3+3x^2=64x+48 I tried and ended up with x=16,-16, and -3/4. Is that correct?      Log On


   

Question 602579: 4x^3+3x^2=64x+48
I tried and ended up with x=16,-16, and -3/4. Is that correct?
Answer by Alan3354(69443) About Me  (Show Source):
You can put this solution on YOUR website!
4x^3+3x^2=64x+48
I tried and ended up with x=16,-16, and -3/4. Is that correct?
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Sub 16 for x and see.
4*16^3 + 3*16^2 =? 64*16 + 48
16384 + 768 =? 1024 + 48
No.