SOLUTION: 3x^2-7x=0 3x^2+33=2x^2+14x (x-3)^2=9 (3x-6)^2=4x^2

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Question 59583This question is from textbook college algebra
: 3x^2-7x=0
3x^2+33=2x^2+14x
(x-3)^2=9
(3x-6)^2=4x^2 This question is from textbook college algebra

Answer by funmath(2933) About Me  (Show Source):
You can put this solution on YOUR website!
3x%5E2-7x=0 Factor out the GCF
x(3x-7)=0 Set each part = to 0 and solve for x
x=0 and 3x-7=0
x=0 and 3x-7+7=0+7
x=0 and 3x=7
x=0 and 3x/3=7/3
x=0 and x=7/3
:
3x%5E2%2B33=2x%5E2%2B14x Set the problem = to 0
-2x%5E2%2B3x%5E2%2B33=-2x%5E2%2B2x%5E2%2B14x
x%5E2%2B33=14x
x%5E2-14x%2B33=14x-14x
x%5E2-14x%2B33=0 Factor
(x-11)(x-3)=0 Set each parentheses = 0 and solve for x.
x-11=0 and x-3=0
x-11+11=0+11 and x-3+3=0+3
x=11 and x=3
:
%28x-3%29%5E2=9 use the square root property, take the square root of both sides.
sqrt%28%28x-3%29%5E2%29=%2B-sqrt%289%29
x-3=+\-3
x-3+3=3+\-3
x=3-3 and x=3+3
x=0 and x=6
:
%283x-6%29%5E2=4x%5E2 Square the left
%283x-6%29%283x-6%29=4x%5E2
3x%283x-6%29-6%283x-6%29=4x%5E2
9x%5E2-18x-18x%2B36=4x%5E2
9x%5E2-36x%2B36=4x%5E2 Set = to 0
9x%5E2-4x%5E2-36x%2B36=4x%5E2-4x%5E2
5x%5E2-36x%2B36=0 Factor, I'm using the ac, arch, or grouping method.
5x%5E2-30x-6x%2B36=0
5x%28x-6%29-6%28x-6%29=0
%28x-6%29%285x-6%29=0 set each parentheses = to 0 and solve for x.
x-6=0 and 5x-6=0
x-6+6=0+6 and 5x-6+6=0+6
x=6 and 5x=6
x=6 and 5x/5=6/5
x=6 and x=6/5
:
Happy Calculating!!!