Question 58658: Could someon help me PLZ
graph y=2(x+5)^-3 and label the vertex and all exact interceps, not to scale on the Y axis
Thank you
Found 2 solutions by Edwin McCravy, funmath:
Answer by Edwin McCravy(20055)   (Show Source):
You can put this solution on YOUR website! Could someon help me PLZ
graph y = 2(x+5)^-3 and label
the vertex and all exact
intercepts, not to scale on
the Y axis
Thank you
There is no "vertex". There is no x-intercept.
The y-intercept is
(0, 2/125). Since the equation is equivalent to
2
y = ----------
(x + 5)³
The denominator becomes zero at x = -5, thus the
vertical line whose equation is x = -5 is a
vertical asymptote.
Since the degree of the denominator, 2, is of
greater than the degree of the numerator, 0, the
x-axis, whose equatrion is y = 0, is the
horizontal asymptote.
Find some points and you get the graph below.
The vertical line is the vertical asymptote. The
y-intercept (0, 2/125) is so close to the
origin that it hardly discernable. The curve
does not really coincide with the x-axis but is
so close to it, there is no way to indicate
that it is not actually coinciding with it.
Edwin
Answer by funmath(2933)  (Show Source):
You can put this solution on YOUR website! graph y=2(x+5)^-3 and label the vertex and all exact interceps, not to scale on the Y axis
On the off chance that you meant to type y=2(x+5)^2-3, I'm going to give this a try.
 is vertex form, where the vertex is (h,k)
Vertex: (h,k)=(-5,-3)
:
Y-intercepts happen when x=0, let x=0 and solve for y.
 There is a y-intercept at (0,47)
:
x-intercepts happen when y=0, let y=0 and solve for x using the square root property:
 Some teachers are happy here.
The x intercepts are at (-5-sqrt(6)/2,0) and (-5+sqrt(6)/2,0)
Happy Calculating!!!
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