SOLUTION: Hi.. Im stuck on a problem {{{5x^2/2+2y^2/5=10}}} I see that I could get somewhere with that because 5 can go into 10 2 times, so something with that but I just dont know how to

Algebra ->  Quadratic Equations and Parabolas  -> Quadratic Equations Lessons  -> Quadratic Equation Lesson -> SOLUTION: Hi.. Im stuck on a problem {{{5x^2/2+2y^2/5=10}}} I see that I could get somewhere with that because 5 can go into 10 2 times, so something with that but I just dont know how to      Log On


   

Question 5848: Hi..
Im stuck on a problem 5x%5E2%2F2%2B2y%5E2%2F5=10
I see that I could get somewhere with that because 5 can go into 10 2 times, so something with that but I just dont know how to start.
Please Help Me
THANK-YOU.
xoxo
Melissa
Answer by longjonsilver(2297) About Me  (Show Source):
You can put this solution on YOUR website!
you need to have 1x^2 term and 1y^2 term...I do not think you can achieve this, so we will not be able to write this in standard form.

What you can do is get it to 25x%5E2+%2B+4y%5E2+=+10%5E2 or %285x%29%5E2+%2B+%282y%29%5E2+=+10%5E2.

jon.