SOLUTION: My paper says: Find the value of the discriminant for 9x^2+1=6x. Then describe the number and type of roots for the equation..... I already found the discriminant to be -72 i just
Question 583145: My paper says: Find the value of the discriminant for 9x^2+1=6x. Then describe the number and type of roots for the equation..... I already found the discriminant to be -72 i just dont know how to do the last part Found 2 solutions by solver91311, Alan3354:Answer by solver91311(24713) (Show Source):
The first thing for you to do is to write back and tell me how you managed to get out of
and how you managed to get anything involving when you didn't take a square root anywhere.
Use the following to determine the nature of the roots:
Find the Discriminant, and evaluate the nature of the roots as follows:
No calculation quick look: If the signs on and are opposite, then guaranteed.
Two real and unequal roots. If is a perfect square, the quadratic factors over (the rationals).
One real root with a multiplicity of two. That is to say that the trinomial is a perfect square and has two identical factors. Presuming rational coefficients, the root will be rational as well.
A conjugate pair of complex roots of the form where is the imaginary number defined by
John
My calculator said it, I believe it, that settles it
You can put this solution on YOUR website! Find the value of the discriminant for 9x^2+1=6x. Then describe the number and type of roots for the equation..... I already found the discriminant to be -72 i just dont know how to do the last part
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Disc = 6^2 - 4*9*1 = 0
Not -72
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Disc = 0 --> 2 real roots, same value
For this eqn, x = 1/3, 1/3
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Or, x = 1/3 multiplicity 2
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