SOLUTION: 2x^2+12x+1=0

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Question 580406: 2x^2+12x+1=0
Answer by dfrazzetto(283) About Me  (Show Source):
You can put this solution on YOUR website!
2x^2+12x+1=0
Not factorable, use quadratic solver:
Solved by pluggable solver: SOLVE quadratic equation with variable
Quadratic equation ax%5E2%2Bbx%2Bc=0 (in our case 2x%5E2%2B12x%2B1+=+0) has the following solutons:

x%5B12%5D+=+%28b%2B-sqrt%28+b%5E2-4ac+%29%29%2F2%5Ca

For these solutions to exist, the discriminant b%5E2-4ac should not be a negative number.

First, we need to compute the discriminant b%5E2-4ac: b%5E2-4ac=%2812%29%5E2-4%2A2%2A1=136.

Discriminant d=136 is greater than zero. That means that there are two solutions: +x%5B12%5D+=+%28-12%2B-sqrt%28+136+%29%29%2F2%5Ca.

x%5B1%5D+=+%28-%2812%29%2Bsqrt%28+136+%29%29%2F2%5C2+=+-0.0845240525773496
x%5B2%5D+=+%28-%2812%29-sqrt%28+136+%29%29%2F2%5C2+=+-5.91547594742265

Quadratic expression 2x%5E2%2B12x%2B1 can be factored:
2x%5E2%2B12x%2B1+=+2%28x--0.0845240525773496%29%2A%28x--5.91547594742265%29
Again, the answer is: -0.0845240525773496, -5.91547594742265. Here's your graph:
graph%28+500%2C+500%2C+-10%2C+10%2C+-20%2C+20%2C+2%2Ax%5E2%2B12%2Ax%2B1+%29