SOLUTION: I am trying to re-write the following formula into a quadratic equtation and I seemed lost. ((48/n)+3)(n-2)= ((48/n)+3)(n-2)-48

Algebra ->  Quadratic Equations and Parabolas  -> Quadratic Equations Lessons  -> Quadratic Equation Lesson -> SOLUTION: I am trying to re-write the following formula into a quadratic equtation and I seemed lost. ((48/n)+3)(n-2)= ((48/n)+3)(n-2)-48      Log On


   

Question 5791: I am trying to re-write the following formula into a quadratic equtation and I seemed lost.

((48/n)+3)(n-2)= ((48/n)+3)(n-2)-48
Answer by ichudov(507) About Me  (Show Source):
You can put this solution on YOUR website!
%0D%0A+%2848%2Fn%2B3%29%28n-2%29+=+%2848%2Fn%2B3%29%28n-2%29-48%0D%0A
that's an impossible equation. If I use a instead of (48/n+3)*(n-2), we get a=a-48, it makes no sense. Can you double check what you typed?