SOLUTION: What is the vertex of x-3=2(y+1)^? What is the vertex of y+1=1/2(x-3)^? What is the vertex of x=1/2y^-y+3?
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-> SOLUTION: What is the vertex of x-3=2(y+1)^? What is the vertex of y+1=1/2(x-3)^? What is the vertex of x=1/2y^-y+3?
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Question 577599
:
What is the vertex of x-3=2(y+1)^?
What is the vertex of y+1=1/2(x-3)^?
What is the vertex of x=1/2y^-y+3?
Answer by
solver91311(24713)
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You can
put this solution on YOUR website!
First thing: "^" does NOT mean "squared," "^" means "raised to the power of the quantity that follows". Hence, "^2" means "squared".
The vertex form of a parabola with a horizontal axis of symmetry and a vertex at
is:
Rewrite your given equation:
and determine the vertex by inspection.
John
My calculator said it, I believe it, that settles it