SOLUTION: Solve the quadratic equation 2x^2-3x-2=0 in quadratic "form" . How so i solve this problem. If you can please show me step from step.

Algebra ->  Quadratic Equations and Parabolas  -> Quadratic Equations Lessons  -> Quadratic Equation Lesson -> SOLUTION: Solve the quadratic equation 2x^2-3x-2=0 in quadratic "form" . How so i solve this problem. If you can please show me step from step.      Log On


   

Question 574851: Solve the quadratic equation 2x^2-3x-2=0 in quadratic "form" . How so i solve this problem. If you can please show me step from step.
Answer by ankor@dixie-net.com(22740) About Me  (Show Source):
You can put this solution on YOUR website!
Solve the quadratic equation 2x^2-3x-2=0 in quadratic "form" .
How so i solve this problem.
If you can please show me step from step.
:
2x^2 - 3x - 2 = 0; this form ax^2 + bx + c = 0; therefore
a = 2; b = -3; c = -2
the quadratic formula:
x+=+%28-b+%2B-+sqrt%28+b%5E2-4%2Aa%2Ac+%29%29%2F%282%2Aa%29+
Replace a, b, c
x+=+%28-%28-3%29+%2B-+sqrt%28-3%5E2-4%2A2%2A-2+%29%29%2F%282%2A2%29+
Do the math, minus a minus is a plus
x+=+%283+%2B-+sqrt%289-%28-16%29+%29%29%2F4+
;
x+=+%283+%2B-+sqrt%289%2B16+%29%29%2F4+
:
x+=+%283+%2B-+sqrt%2825+%29%29%2F4+
Find the square root, we have two solutions
x+=+%283+%2B+5+%29%29%2F4+
x = 8%2F4
x = 2
and
x+=+%283+-+5+%29%29%2F4+
x = %28-2%29%2F4
x = -.5
:
:
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