SOLUTION: 1. If x = 3 and x = -5, then form a quadratic equation. 2. What type of solution do you get for quadratic equations where D < 0? Give reasons for your answer. Also provide an e

Algebra ->  Quadratic Equations and Parabolas  -> Quadratic Equations Lessons  -> Quadratic Equation Lesson -> SOLUTION: 1. If x = 3 and x = -5, then form a quadratic equation. 2. What type of solution do you get for quadratic equations where D < 0? Give reasons for your answer. Also provide an e      Log On


   



Question 57155: 1. If x = 3 and x = -5, then form a quadratic equation.
2. What type of solution do you get for quadratic equations where D < 0? Give reasons for your answer. Also provide an example of such a quadratic equation and find the solution of the equation.
3. Create a real-life situation that fits into the equation (x + 3)(x - 4) = 0 and express the situation as the same equation.

Answer by ankor@dixie-net.com(22740) About Me  (Show Source):
You can put this solution on YOUR website!
If x = 3 and x = -5, then form a quadratic equation.
FOIL (x-3)(x+5) = x^2 + 2x -15 = 0
:
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2. What type of solution do you get for quadratic equations where D < 0? Give reasons for your answer.
:
The equation has two complex number solutions. The Discriminant is part of the quadratic formula, so you end up with the square root of a neg number.
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Also provide an example of such a quadratic equation and find the solution of the equation.
:
2x^2 - x + 5 = 0
Using the quadratic formula your solutions are:
x = %281-i%2ASqRt%2839%29%29%2F4 and %281%2Bi%2ASqRt%2839%29%29%2F4
:
:
3. Create a real-life situation that fits into the equation (x + 3)(x - 4) = 0 and express the situation as the same equation:
:
The area of a rectangle is 12 sq ft; where the width is 1 ft shorter than the
width: W = (L - 1)
Area = L * (L-1) = 12
L^2 - L - 12 = 0
(L + 3)(L - 4) = 0
L = +4