SOLUTION: Find two consecutive negative integers such that the sum of their squares is 113.

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Question 566320: Find two consecutive negative integers such that the sum of their squares is 113.
Answer by ad_alta(240) About Me  (Show Source):
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Let 'n' be the smaller integer. Then n^2+(n+1)^2=113. Thus 2n^2+2n-112=0. Using the quadratic formula, we get n=-8. The two consecutive negative integers are -8 and -7.