SOLUTION: An object is released from a plane at an altitude of 1600 ft. The initial velocity is 0 ft/s. How many seconds later will the object hit the ground? Use the formula d=vt+16t^2,

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Question 56269This question is from textbook Beginning Algebra with applications
: An object is released from a plane at an altitude of 1600 ft. The initial velocity is 0 ft/s. How many seconds later will the object hit the ground?
Use the formula d=vt+16t^2, where d is the distance in feet, v is the initial velocity in feet per second, and t is the time in seconds This question is from textbook Beginning Algebra with applications

Answer by funmath(2933) About Me  (Show Source):
You can put this solution on YOUR website!
An object is released from a plane at an altitude of 1600 ft. The initial velocity is 0 ft/s. How many seconds later will the object hit the ground?
:
Use the formula d=vt%2B16t%5E2, where d is the distance in feet, v is the initial velocity in feet per second, and t is the time in seconds
:
d=1600, v=0
1600=%280%29t%2B16t%5E2
1600=16t%5E2
1600%2F16=16t%5E2%2F16
100=t%5E2
%2B-sqrt%28100%29=sqrt%28t%5E2%29 -time is meaningless so go with +.
10=t
The object will hit the ground in 10 s.
Happy Calculating!!!