SOLUTION: please solve this equation 64k^2+112k+49=0, thank you

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Question 560369: please solve this equation 64k^2+112k+49=0, thank you
Found 2 solutions by subudear, kkasko:
Answer by subudear(62) About Me  (Show Source):
You can put this solution on YOUR website!
64k^2+112k+49=0
There are different ways to solve this problem but I like and advise to use method of finding roots uisng formula.
roots, alpha = [-b + sqrt(b^2 - 4ac)]/2a , beta = [-b - sqrt(b^2 - 4ac)]/2a where a = 64, b = 112 and c = 49
alpha = [-b + sqrt(b^2 - 4ac)]/2a = [-112 + sqrt(112^2 - 4*64*49)]/2*64 = -7/8
beta = [-b - sqrt(b^2 - 4ac)]/2a = [-112 - sqrt(112^2 - 4*64*49)]/2*64 = -7/8
the solution is x = -7/8, -7/8

Answer by kkasko(46) About Me  (Show Source):
You can put this solution on YOUR website!
please solve this equation 64k^2+112k+49=0, thank you
Plug into the quadratic formula x=%28-b+%2B-+sqrt%28+b%5E2-4%2Aa%2Ac%29%29%2F%282%2Aa%29
k=-112+%2B-+sqrt%28+112%5E2-4%2A64%2A49%29%2F%282%2A64%29
k=-112+%2B-+sqrt%28+12544-12544%29%2F%28128%29
k=-112+%2B-+sqrt%280%29%2F%28128%29
Simplify -112/128 by dividing the numerator -112 and denominator 128 by 16
k=%28-7+%2B-+sqrt%280%29%2F%288
Since the discriminant is zero. The equation will have 2 equal roots. Where only one root shows.
k=%28-7+%2B-+sqrt%280%29%2F%288
k=-.875 Math Fract =-7/8
k=-7/8 k=-7/8