SOLUTION: solve the equation by completeing the square: 7x^2+10x=-2

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Question 548975: solve the equation by completeing the square:
7x^2+10x=-2

Found 3 solutions by mananth, josmiceli, mathie123:
Answer by mananth(16946) About Me  (Show Source):
You can put this solution on YOUR website!
7x^2+10x=-2
/7
x^2+(10/7)x= -2/7
7 X^2 + 10 x = -2
/7
1 X^2 + 10/7 x+b= - 2/7
Calculate third term (b)
2 * b * 1 = 10/7
2 b = 10/7
b= 10/7 / 2
b= 5/7
b^2= 25/49

x^2 + 10/7 x+ 25/49 =- 2/7+ 25/49
(x+ 5/7 )^2= 11/49
( x+ 5/7) = sqrt(11)/7
x= - 5/7 +/- sqrt(11)/7

Answer by josmiceli(19441) About Me  (Show Source):
You can put this solution on YOUR website!
+7x%5E2+%2B+10x+=+-2+
Divide both sides by 7
+x%5E2+%2B+%2810%2F7%29%2Ax+=+-2%2F7+
Take 1/2 of the coefficient of x,
square it, and add it to both sides
+x%5E2+%2B+%2810%2F7%29%2Ax+%2B+%285%2F7%29%5E2+=+-2%2F7+%2B+%285%2F7%29%5E2+
+x%5E2+%2B+%2810%2F7%29%2Ax+%2B+%285%2F7%29%5E2+=+-14%2F49+%2B+25%2F49+
+x%5E2+%2B+%2810%2F7%29%2Ax+%2B+%285%2F7%29%5E2+=+11%2F49+
+%28+x+%2B+%285%2F7%29+%29%5E2+=+11%2F49+
Take the square root of both sides
+x+%2B+5%2F7+=+sqrt%2811%29%2F7+
+x+=+%28+-5+%2B-+sqrt%2811%29+%29+%2F+7+
Here's a plot of equation:
+graph%28+400%2C+400%2C+-3%2C+3%2C+-3%2C+7%2C+7x%5E2+%2B+10x+%2B+2+%29+

Answer by mathie123(224) About Me  (Show Source):
You can put this solution on YOUR website!
7x%5E2%2B10x=-2
We will first put everything on one side of the equation (as in most classes, students are most familiar with completely the square when it is in the form ax^2+bx+c
this gives us:
7x%5E2%2B10x%2B2=0
Now we need to make the constant in front of x^2 1, so we will factor out a 7 from our first two terms:
7%28x%5E2%2B10%2F7%2Ax%29%2B2=0
Now the rules for completing the square say we must take the constant in front of the x and square one half of this number and add and subtract this number.
So our constant is 10/7. One half of 10/7 is
10/7*1/2=10/14
and this squared is
(10/14)^2=(5/7)^2=25/49
So we will add and subtract this number (so essentially we are adding 0 to our equation, which does not change it).
7%28x%5E2%2B10%2F7%2Ax%2B25%2F49-25%2F49%29%2B2=0
We will now take our -25/49 out of the bracket (remembering to multiply it by 7 when we take it out). this leaves:
7%28x%5E2%2B10%2F7%2Ax%2B25%2F49%29%2B2-25%2F49%2A7=0
Almost there....
We will complete the square inside of the brackets. Essentially we just write it in the form (x+a)^2 where a is 1/2 of the constant in front of the x term originally (we found this was 10/14=5/7
So we have:
7%28x%2B5%2F7%29%5E2%2B2-25%2F7=0
7%28x%2B5%2F7%29%5E2%2B14%2F7-25%2F7=0
7%28x%2B5%2F7%29%5E2-11%2F7=0

Now it is just solving for x, so let's isolate x:
7%28x%2B5%2F7%29%5E2-11%2F7=0
7%28x%2B5%2F7%29%5E2=11%2F7
7%28x%2B5%2F7%29%5E2%2F7=%2811%2F7%29%2F7
%28x%2B5%2F7%29%5E2=11%2F49
%28x%2B5%2F7%29=%2B-sqrt%2811%2F49%29
x=%2B-sqrt%2811%2F49%29-5%2F7

This can be simplified on your calculator... but I will leave that to you.
Hopefully this helps... let me know if you are still unsure.