SOLUTION: A baseball is popped straight up with an initial velocity of 32 feet per second, then its height above the ground is a function of time given by s(t)=-16t^2+32t . Graph this func

Algebra ->  Quadratic Equations and Parabolas  -> Quadratic Equations Lessons  -> Quadratic Equation Lesson -> SOLUTION: A baseball is popped straight up with an initial velocity of 32 feet per second, then its height above the ground is a function of time given by s(t)=-16t^2+32t . Graph this func      Log On


   



Question 544: A baseball is popped straight up with an initial velocity of 32 feet per second, then its height above the ground is a function of time given by s(t)=-16t^2+32t . Graph this function for 0 less than or equal t less than or equal 2 . What is the maximum height reached by this baseball?

Answer by citychic3(8) About Me  (Show Source):
You can put this solution on YOUR website!
i dont have the graph thing down yet so ill just tell you to make a table of values (a table that has numbers for each x point and for each y point; so like in this graph x=-2 and y=0 or (-2,0)) here are some more points that are on your graph. (-1,-16)(0,0)(1,48) (-3,48) if you have a graphing calculator you can figure this out easily and the maximum height but here's how u can also do it. you will graph it then make dotted lines through Y=0 and X=2 then see what the highest number on the line in the box you just made is.