SOLUTION: It's my very first time seeking help on this website because I am truly lost. The question from my book says that "the radicand of the quadratic formula, b^2 - 4ac, can be used to

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Question 541946: It's my very first time seeking help on this website because I am truly lost. The question from my book says that "the radicand of the quadratic formula, b^2 - 4ac, can be used to determine whether +ax%5E2+%2B+bx+%2B+c+=+a has solutions that are rational, irrational, or not real numbers." I haven't been able to solve the problem on this website because it's saying that the first coefficient is zero. It's also asking me to explain how this works. And if it possible to determine the kinds of answers that one will obtain to a quadratic equation without actually solving the equation. I would greatly appreciate any help I can get.
Answer by Alan3354(69443) About Me  (Show Source):
You can put this solution on YOUR website!
The question from my book says that "the radicand of the quadratic formula, b^2 - 4ac, can be used to determine whether +ax%5E2+%2B+bx+%2B+c+=+a has solutions that are rational, irrational, or not real numbers." I haven't been able to solve the problem on this website because it's saying that the first coefficient is zero. It's also asking me to explain how this works. And if it possible to determine the kinds of answers that one will obtain to a quadratic equation without actually solving the equation.
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I think you mean +ax%5E2+%2B+bx+%2B+c+=+0, not = a
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The radicand is called the determinant.
It's b^2 - 4ac
If it's >0, you have 2 real answers.
If it's =0, you have the same real root twice.
If it's <0, you have 2 complex roots.