SOLUTION: Identify the vertex and the axis of symmetry of the quadratic function. f(x)=(x+8)^2-7 The vertex is: The axis of symmetry is:

Algebra ->  Quadratic Equations and Parabolas  -> Quadratic Equations Lessons  -> Quadratic Equation Lesson -> SOLUTION: Identify the vertex and the axis of symmetry of the quadratic function. f(x)=(x+8)^2-7 The vertex is: The axis of symmetry is:      Log On


   

Question 540645: Identify the vertex and the axis of symmetry of the quadratic function.
f(x)=(x+8)^2-7
The vertex is:
The axis of symmetry is:
Answer by oberobic(2304) About Me  (Show Source):
You can put this solution on YOUR website!
f(x) = (x+8)^2 -7
f(x) = x^2 +16x + 64 -7
f(x) = x^2 +16x + 57
.
+graph%28500%2C500%2C-12%2C5%2C-12%2C5%2Cx%5E2%2B16x%2B57%29+
.
The axis is symmetry is defined by x = -b/2a
.
-b/2a = -16/2 = -8
.
The vertex is found by finding f(x) for x = -8.
.
f(x) = (-8)^2 +16(-8) + 57
f(x) = 64 -128 + 57
f(x) = -7
.
Vertex = (-8,-7)
.
Done.