You can put this solution on YOUR website! If a bus traveled 10km/h faster, it would take 2 hours less time to make a 315km trip.
What is its speed?
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Let s = the speed of the bus
then
(s+10) = the faster speed
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Write time equation, time = dist/speed
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Actual time - faster time = 2 hrs - = 2
multiply by s(s+10)
s(s+10)* - s(s+5)* = 2s(s+10)
Cancel the denominators and you have
315(s+10) - 315s = 2s^2 + 20s
315s + 3150 - 315s = 2s^2 + 20s
0 = 2s^2 + 20s - 3150
Simplify, divide by 2
s^2 + 10s - 1575 = 0
Factors to
(s+45)(s-35) = 0
The positive solution
s = 35 mph is the actual bus speed
:
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Check this by finding the times at each speed
315/35 = 9 hrs
315/45 = 7 hrs