Find the value of Q
P + R = 4
QP + R = 10
P + QR = 14
This is a system of 3 equations in 3 unknowns.
Solve the first equation for P
P = 4 - R
Substitute (4 - R) for P in the 2nd equation:
QP + R = 10
Q(4 - R) + R = 10
4Q - QR + R = 10
Substitute (4 - R) for P in the 3rd equation:
P + QR = 14
(4 - R) + QR = 14
4 - R + QR = 14
-R + QR = 10
Now we have this system of two equations in 2 unknowns
4Q - QR + R = 10
-R + QR = 10
Now we write the terms on the left of the second equation
in the opposite order, draw a line and add vertically
term by term:
4Q - QR + R = 10
QR - R = 10
----------------
4Q = 20
Q = 5
Substitute 5 for Q in the equation QR - R = 10:
QR - R = 10
5R - R = 10
4R = 10
R = 10/4
R = 5/2
Substitute 5/2 for R in the equation P = 4 - R:
P = 4 - R
P = 4 - 5/2
P = 8/2 - 5/2
P = 3/2
So (P, Q, R) = (3/2, 5, 5/2)
Edwin