SOLUTION: Find the vertex the line of symmetry, the maximum or minimum value of the f(x). Graph the function. f(x)= 1/4(x+2)^2+4

Algebra ->  Quadratic Equations and Parabolas  -> Quadratic Equations Lessons  -> Quadratic Equation Lesson -> SOLUTION: Find the vertex the line of symmetry, the maximum or minimum value of the f(x). Graph the function. f(x)= 1/4(x+2)^2+4       Log On


   

Question 534399: Find the vertex the line of symmetry, the maximum or minimum value of the f(x). Graph the function.
f(x)= 1/4(x+2)^2+4
Answer by oberobic(2304) About Me  (Show Source):
You can put this solution on YOUR website!
f(x) = 1/4(x+2)^2 +4
f(x) = 1/4(x^2 +4x + 4) + 4
f(x) = 1/4*x^2 +x + 5
.
axis of symmetry = -b/2a
-b/2a = -1/(2*1/4) = -1/(1/2) = -2
vertex = 1/4(-2+2)^2 +4 = 4
(-2,4)
.
+graph%28500%2C500%2C-10%2C10%2C-10%2C10%2C1%2F4%2A%28x%2B2%29%5E2%2B4%29+