SOLUTION: -4x2+8x+3=0
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Question 530293
:
-4x2+8x+3=0
Answer by
stanbon(75887)
(
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):
You can
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-4x2+8x+3=0
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4x^2 - 8x -3 = 0
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x = [8 +- sqrt(64 - 4*4*-3)]/8
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x = [8 +- sqrt(112)]/8
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x = [8 +- sqrt(16*3)]/8
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x = 1 +- (1/2)sqrt(3)
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Cheers,
Stan H.
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