SOLUTION: Please help and solve this graph for me. y=-x^2-2x x;-3 -2 -1 0 1 y;

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Question 52342This question is from textbook Beginnning Algebra
: Please help and solve this graph for me. y=-x^2-2x

x;-3 -2 -1 0 1
y; This question is from textbook Beginnning Algebra

Found 2 solutions by funmath, venugopalramana:
Answer by funmath(2933) (Show Source):
You can put this solution on YOUR website!
Substitute the x values into the equation and solve for y. Plot these (x,y) coordinates and connect the dots.
For x=-3;
y=-(-3)^2-2(-3)
y=-(-3)(-3)-2(-3)
y=-9+6
y=-3
Plot:(-3,-3)
For x=-2;
y=-(-2)^2-2(-2)
y=-(-2)(-2)-2(-2)
y=-4+4
y=0
Plot:(-2,0)
For x=-1
y=-(-1)^2-2(-1)
y=-(-1)(-1)-2(-1)
y=-1+2
y=1
Plot:(-1,1)
For x=0
y=-(0)^2-2(0)
y=-0+0
y=0
Plot:(0,0)
For x=1
y=-(1)^2-2(1)
y=-(1)(1)-2(1)
y=-1-2
y=-3
Plot:(1,-3)

Answer by venugopalramana(3286) (Show Source):
You can put this solution on YOUR website!
Please help and solve this graph for me. y=-x^2-2x
x; -3 -2 -1 0 1
y;=-x^2-2x.....-3..0..3.0.-3
graph is given below..blue line..its x intercepts are -2 and 0 ..hence x=0 and x=-2 are the solutions.2 more graphs...green and red lines are plotted here for
y=x^2 ....green line...and y = -2x....red line whose intersection at x=0 and x= -2 confirm the same solution in another way