SOLUTION: jojo's java hut mixed Kona coffee beans worth$6/pound with columbian beans with $8.80/pound. the resulting mixture was 16 pounds of a delightful breakfast blend worth $6.70/pound.

Algebra ->  Quadratic Equations and Parabolas  -> Quadratic Equations Lessons  -> Quadratic Equation Lesson -> SOLUTION: jojo's java hut mixed Kona coffee beans worth$6/pound with columbian beans with $8.80/pound. the resulting mixture was 16 pounds of a delightful breakfast blend worth $6.70/pound.      Log On


   

Question 519364: jojo's java hut mixed Kona coffee beans worth$6/pound with columbian beans with $8.80/pound. the resulting mixture was 16 pounds of a delightful breakfast blend worth $6.70/pound. how many pounds of each type of bean were used?
Answer by scott8148(6628) About Me  (Show Source):
You can put this solution on YOUR website!
k + c = 16

k(6) + c(8.8) = 16(6.7)