SOLUTION: what is the vertex of f(x)=-x^2+8x-19

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Question 515228: what is the vertex of f(x)=-x^2+8x-19
Answer by stanbon(75887) About Me  (Show Source):
You can put this solution on YOUR website!
what is the vertex of f(x)=-x^2+8x-19
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a = -1 ; b = 8 ; c = -19
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Vertex occurs where x = -b/(2a) = -8/(2*-1) = 4
f(4) = -16 + 32 -19 = -3
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Vertex at (4,-3)
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Cheers,
Stan H.
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