SOLUTION: 2) For the function y = x2 - 4x - 5, perform the following tasks: a) Put the function in the form y = a(x - h)2 + k. Answer: Show work in this space b) What

Algebra ->  Quadratic Equations and Parabolas  -> Quadratic Equations Lessons  -> Quadratic Equation Lesson -> SOLUTION: 2) For the function y = x2 - 4x - 5, perform the following tasks: a) Put the function in the form y = a(x - h)2 + k. Answer: Show work in this space b) What       Log On


   

Question 51408:
2) For the function y = x2 - 4x - 5, perform the following tasks:
a) Put the function in the form y = a(x - h)2 + k.
Answer:
Show work in this space



b) What is the equation for the line of symmetry for the graph of this function?
Answer:



c) Graph the function using the equation in part a. Explain why it is not necessary to plot points to graph when using y = a (x – h)2 + k.
Show graph here.


Explanation of graphing.




d) In your own words, describe how this graph compares to the graph of y = x2?
Answer:
Answer by venugopalramana(3286) About Me  (Show Source):
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2)For the function y = x2 - 4x - 5
a)Put the function in the form y = a(x - h)2 + k.For the function y = x2 - 4x - 5
={X^2-2(X)(2)+2^2}-2^2-5
=(X-2)^2-9
A=1....H=2.......K=-9
b)What is the equation for the line of symmetry or the graph of this function?
X-2=0....OR...X=2 IS THE LINE OF SYMMETRY
c)Graph the function using the equation in part a. Why it is not necessary to plot points to graph when using y = a (x – h)2 + k.
+graph%28+500%2C+500%2C+-10%2C+10%2C+-10%2C+10%2C+x%5E2-4x-5%2Cx%5E2%29+
DRAW LINE OF SYMMETRY X=2..PLOT VERTEX AT (2,-9)..PLOT CURVE SYMMETRICALLY ALONG THE LINE OF SYMMETRY TAKING THE 2 INTERCEPT POINTS ON THE X AXIS AS
X-2=+3 OR -3....THAT IS X=5 AND -1
d)Describe how this graph compares to the graph of y = x2?
IT IS PARALLEL WITH A SHIFT IN VERTEX FROM (0,0) TO (2,-9)