SOLUTION: How do I divide this equation using a+bi form 6/2+4i

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Question 5098: How do I divide this equation using a+bi form 6/2+4i
Answer by rapaljer(4671) About Me  (Show Source):
You can put this solution on YOUR website!
A clever trick is to factor the denominator and reduce the fraction first.

6%2F%282%281%2B2i%29%29+ = 3%2F%281%2B2i%29

Now multiply numerator and denominator by the conjugate of the denominator, which is 1-2i.
3%2F+%281%2B2i%29+%2A+%281-2i+%29+%2F%281-2i%29
+%283+-+6i%29+%2F+%281+-+4i%5E2%29, where i%5E2+=+-1
+%283+-+6i%29%2F5
3%2F5+-+%286%2F5%29+i+

This is the old way to solve the problem. It is MUCH easier with a graphing calculator!!

R^2 at SCC