SOLUTION: Solve by factoring: 2a^2-3a=-5 Guys I really need help quickly please help.

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Question 509170: Solve by factoring:
2a^2-3a=-5
Guys I really need help quickly please help.
Found 2 solutions by Alan3354, swincher4391:
Answer by Alan3354(69443) About Me  (Show Source):
You can put this solution on YOUR website!
Solve by factoring:
2a^2-3a=-5
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Solve by factoring:
2a^2-3a+5 = 0
That can't be factored.
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Solved by pluggable solver: SOLVE quadratic equation (work shown, graph etc)
Quadratic equation ax%5E2%2Bbx%2Bc=0 (in our case 2x%5E2%2B-3x%2B5+=+0) has the following solutons:

x%5B12%5D+=+%28b%2B-sqrt%28+b%5E2-4ac+%29%29%2F2%5Ca

For these solutions to exist, the discriminant b%5E2-4ac should not be a negative number.

First, we need to compute the discriminant b%5E2-4ac: b%5E2-4ac=%28-3%29%5E2-4%2A2%2A5=-31.

The discriminant -31 is less than zero. That means that there are no solutions among real numbers.

If you are a student of advanced school algebra and are aware about imaginary numbers, read on.


In the field of imaginary numbers, the square root of -31 is + or - sqrt%28+31%29+=+5.56776436283002.

The solution is , or
Here's your graph:
graph%28+500%2C+500%2C+-10%2C+10%2C+-20%2C+20%2C+2%2Ax%5E2%2B-3%2Ax%2B5+%29

Answer by swincher4391(1107) About Me  (Show Source):
You can put this solution on YOUR website!
Solve the equation for 0.
2a^2 - 3a + 5 = 0
Take a look at your equation again... this is not factorable with integers.
Please, repost.