SOLUTION: An enclosed area is designed using one existing wall, and 72m of fence material. What is the maximum possible area of this enclosure? So I did y=72-2x, hence A=(x)(72-2x). Then, I

Algebra ->  Quadratic Equations and Parabolas  -> Quadratic Equations Lessons  -> Quadratic Equation Lesson -> SOLUTION: An enclosed area is designed using one existing wall, and 72m of fence material. What is the maximum possible area of this enclosure? So I did y=72-2x, hence A=(x)(72-2x). Then, I       Log On


   

Question 508808: An enclosed area is designed using one existing wall, and 72m of fence material. What is the maximum possible area of this enclosure? So I did y=72-2x, hence A=(x)(72-2x). Then, I factored it out to A=72x-2x^2. I graphed it but i got 648 as the maximum area and its wrong.
Found 2 solutions by scott8148, edjones:
Answer by scott8148(6628) About Me  (Show Source):
You can put this solution on YOUR website!
your solution looks good

can you show what the "correct" answer is?

Answer by edjones(8007) About Me  (Show Source):
You can put this solution on YOUR website!
you are correct. 648 m^2 is the answer.
.
Ed