Question 490126: I am having trouble solving the following: Please help me understand
Height , h metres of a model rocket above ground, t = seconds after launching is given by the equation h=4t(50-t).
Sketch the graph show the co-ordinates of all intercepts and turning point.
I need to find the greatest height the rocket reaches, after how long does the rocket reach its greatest height and how long does the rockets flight last.
I have not come across a quadratic equation in this form before and it is confusing me.
Any help you can give me would be most appreciated.
Thank you.
Answer by stanbon(75887)   (Show Source):
You can put this solution on YOUR website! Height , h metres of a model rocket above ground, t = seconds after launching is given by the equation h(t) = 4t(50-t).
Sketch the graph show the co-ordinates of all intercepts and turning point.
h(t) = -4t^2+200t
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Vertical intercept: (0,0)
Horizontal intercept: (0,0)(50,0)
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I need to find the greatest height the rocket reaches, after how long does the rocket reach its greatest height and how long does the rockets flight last.
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Max occurs when t = -b/(2a) = -200/(2*-4) = 25 seconds
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Max height: h(25) = 4*25(25) = 2500 ft
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length of flight: 50 seconds
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Cheers,
Stan H.
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