SOLUTION: a picture has a height that is 4/3 its width.it is to be enlarged to have an area of 192 square inches. what will be the dimensions of the enlargement?

Algebra ->  Quadratic Equations and Parabolas  -> Quadratic Equations Lessons  -> Quadratic Equation Lesson -> SOLUTION: a picture has a height that is 4/3 its width.it is to be enlarged to have an area of 192 square inches. what will be the dimensions of the enlargement?      Log On


   



Question 480446: a picture has a height that is 4/3 its width.it is to be enlarged to have an area of 192 square inches. what will be the dimensions of the enlargement?
Answer by ankor@dixie-net.com(22740) About Me  (Show Source):
You can put this solution on YOUR website!
a picture has a height that is 4/3 its width.it is to be enlarged to have an area of 192 square inches. what will be the dimensions of the enlargement?
:
The relationship between the width and height should remain the same after the enlargement:
:
Let w = the enlarged width
then
4%2F3w = the enlarged height
:
w*4%2F3w = 192
:
4%2F3w^2 = 192
4w^2 = 3(192
4w^2 = 576
w^2 = 576%2F4
w^2 = 144
w = sqrt%28144%29
w = 12 in is the width
then
4%2F3*12 = 16 in is the height