SOLUTION: How to use the quadratic formula to solve for x if 3x(squared)+35=26x

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Question 478501: How to use the quadratic formula to solve for x if 3x(squared)+35=26x
Found 2 solutions by MathLover1, cleomenius:
Answer by MathLover1(20849) About Me  (Show Source):
You can put this solution on YOUR website!
3x%5E2%2B35=26x...first move 26x to the left
3x%5E2-26x%2B35=0..now use quadratic formula
x+=+%28-b+%2B-+sqrt%28+b%5E2-4%2Aa%2Ac+%29%29%2F%282%2Aa%29+...note: a=3, b=-26 and c=35

x+=+%28-%28-26%29+%2B-+sqrt%28+%28-26%29%5E2-4%2A3%2A35+%29%29%2F%282%2A3%29+

x+=+%2826+%2B-+sqrt%28676-420+%29%29%2F6+

x+=+%2826+%2B-+sqrt%28256%29%29%2F6+

x+=+%2826+%2B-16%29%2F6+

solutions:
x+=+%2826+%2B16%29%2F6+

x+=+42%2F6+

x+=+7
or
x+=+%2826+-16%29%2F6+

x+=+10%2F6+

x+=+5%2F3



+graph%28+500%2C+500%2C+-10%2C+10%2C+-50%2C+50%2C+3x%5E2-26x%2B35%29+





Answer by cleomenius(959) About Me  (Show Source):
You can put this solution on YOUR website!
First put in order.
3x^2 -26x + 35 = 0.
Next, assign a, b, and c.
a = 3
c = -26
c = 35
The formula is (-b +,- (sqrt( b^2 - 4ac))/ 2a
(26 +,- sqrt( (-26)^2 - 4(3)(35) ) / 2(3)

(26 +,- sqrt(676 - 420) ) /6
(26 +,- sqrt ( 256)) / 6.
(26 + 16) /6 = 7
(26 - 16) /6 = 1.667
If you plug these into your original formulas, they will both check out.
Cleomenius.