SOLUTION: Find the vertex line of symmetry maximum or minimum value graph the function f(x)=-2x^2+2x+2

Algebra ->  Quadratic Equations and Parabolas  -> Quadratic Equations Lessons  -> Quadratic Equation Lesson -> SOLUTION: Find the vertex line of symmetry maximum or minimum value graph the function f(x)=-2x^2+2x+2      Log On


   



Question 477365: Find the
vertex
line of symmetry
maximum or minimum value
graph the function
f(x)=-2x^2+2x+2

Answer by lwsshak3(11628) About Me  (Show Source):
You can put this solution on YOUR website!
Find the
vertex
line of symmetry
maximum or minimum value
graph the function
f(x)=-2x^2+2x+2
**
f(x)=-2x^2+2x+2
completing the square
f(x)=-2(x^2-x+1/4)+2+1/2
f(x)=-2(x-1/2)^2+1/2
This is an equation of a parabola of standard form: y=A(x-h)^2+k, with (h,k) being the (x,y) coordinates of the vertex. The negative coefficient of the leading term means the curve opens downward, that is, there is a maximum. A is a multiplier which affects the steepness of the curve.
vertex: (1/2,5/2)
line of symmetry: x=1/2
maximum value: 5/2
See graph below as a visual check on the answers:
..
+graph%28+300%2C+300%2C+-8%2C+8%2C+-8%2C+8%2C-2x%5E2%2B2x%2B2%29+