Question 470787: Find the vertex, the line of symmetry, the maximum or minimum value of the quadratic function, and graph the function
f(x)=4x^2-40x+102
Answer by lwsshak3(11628)   (Show Source):
You can put this solution on YOUR website! Find the vertex, the line of symmetry, the maximum or minimum value of the quadratic function, and graph the function
f(x)=4x^2-40x+102
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f(x)=4x^2-40x+102
Completing the square
f(x)=4(x^2-10x+25)+102-100
f(x)=4(x-5)^2+2
This is a parabola with a vertical axis of symmetry. Opens upward. Standard form:
y=(x-h)^2+k, with (h,k) being the (x,y) coordinates of the vertex.
For given parabola:
vertex: (5, 2)
minimum value=2 at x=5
see graph below as a visual check on answers:
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