SOLUTION: For the function y = x2 - 6x + 8, perform the following tasks: a) Put the function in the form y = a(x - h)2 + k. Answer: Show work in this space. b) What is the

Algebra ->  Quadratic Equations and Parabolas  -> Quadratic Equations Lessons  -> Quadratic Equation Lesson -> SOLUTION: For the function y = x2 - 6x + 8, perform the following tasks: a) Put the function in the form y = a(x - h)2 + k. Answer: Show work in this space. b) What is the       Log On


   



Question 46964: For the function y = x2 - 6x + 8, perform the following tasks:
a) Put the function in the form y = a(x - h)2 + k.
Answer:
Show work in this space.


b) What is the line of symmetry?
Answer:



c) Graph the function using the equation in part a. Explain why it is not necessary to plot points to graph when using y = a (x - h) 2 + k.
Show graph here.

Explanation of graphing.

d) In your own words, describe how this graph compares to the graph of y = x2?
Answer:

Answer by Nate(3500) About Me  (Show Source):
You can put this solution on YOUR website!
a) Put the function in the form y = a(x - h)2 + k.
y = x^2 - 6x + 8
v(-b/2a,f(x))
v(3,-1) so h = 3 and k = -1
a = 1 while b = -6 and c = 8
y+=+a%28x+-+h%29%5E2+%2B+k
y+=+%28x+-+3%29%5E2+-+1
b) What is the line of symmetry?
Since the parabola is vertical, the line of symmetry is equal to the x-term in the vertex. x+=+3
c) Graph the function using the equation in part a. Explain why it is not necessary to plot points to graph when using y = a (x - h) 2 + k.
y+=+%28x+-+3%29%5E2+-+1 in terms: y+=+a%28x+-+h%29%5E2+%2B+k
vertex(h,k)
(distance from vertex to focus or from vertex to directrix = 1%2F4a = 1%2F4
Latus Rectum (distance touching the parabola going through the focus) = |1/a| = 1
graph%28600%2C600%2C-10%2C10%2C-10%2C10%2C%28x+-+3%29%5E2+-+1%29
d) In your own words, describe how this graph compares to the graph of y = x2?
They are both parabolas. They both have the same value for 'a'. y+=+x%5E2 has a different vertex. The Latus Rectum and distances are the same.