SOLUTION: Find the vertex, the line of symmetry, the maximum or minimum value of the quadratic function and graph the function. Help!, these are the only two I do not understand.
f(x)= -x^2
Question 468337: Find the vertex, the line of symmetry, the maximum or minimum value of the quadratic function and graph the function. Help!, these are the only two I do not understand.
f(x)= -x^2+6x+6
f(x)= 2-x^2 Answer by ewatrrr(24785) (Show Source):
Hi,
Using the vertex form of a parabola, where(h,k) is the vertex
f(x)= -x^2+6x+6
f(x)= -[(x-3)^2 -9]+6
f(x)= -(x-3)^2 +15 V(3,15) maximum a = -1 a<0 Parabola opens downward
Line of symmetry x = 3
f(x)= 2-x^2
f(x)= -(x-0)^2 + 2 V(0,2) maximum a = -1 a<0 Parabola opens downward
Line of symmetry x = 0 (y-axis)
