SOLUTION: USE QUADRATIC FORMULA FOR -2X^2+6X-5=0

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Question 467795: USE QUADRATIC FORMULA FOR
-2X^2+6X-5=0

Answer by jorel1380(3719) About Me  (Show Source):
You can put this solution on YOUR website!
-2x2+6x-5=0
Solved by pluggable solver: SOLVE quadratic equation with variable
Quadratic equation ax%5E2%2Bbx%2Bc=0 (in our case -2x%5E2%2B6x%2B-5+=+0) has the following solutons:

x%5B12%5D+=+%28b%2B-sqrt%28+b%5E2-4ac+%29%29%2F2%5Ca

For these solutions to exist, the discriminant b%5E2-4ac should not be a negative number.

First, we need to compute the discriminant b%5E2-4ac: b%5E2-4ac=%286%29%5E2-4%2A-2%2A-5=-4.

The discriminant -4 is less than zero. That means that there are no solutions among real numbers.

If you are a student of advanced school algebra and are aware about imaginary numbers, read on.


In the field of imaginary numbers, the square root of -4 is + or - sqrt%28+4%29+=+2.

The solution is x%5B12%5D+=+%28-6%2B-+i%2Asqrt%28+-4+%29%29%2F2%5C-2+=++%28-6%2B-+i%2A2%29%2F2%5C-2+

Here's your graph:
graph%28+500%2C+500%2C+-10%2C+10%2C+-20%2C+20%2C+-2%2Ax%5E2%2B6%2Ax%2B-5+%29