SOLUTION: Hi I'm working on a take home test right now & i need your help! my problem is {{{ h(x)=(x+3)^2-4 }}} i believe iv found .. Vertex: (-3,4) axis of symmetry: -3 y-intercept: (0

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Question 465873: Hi I'm working on a take home test right now & i need your help!
my problem is +h%28x%29=%28x%2B3%29%5E2-4+
i believe iv found ..
Vertex: (-3,4)
axis of symmetry: -3
y-intercept: (0,5)
&
Domain: all real #s
..but im not sure my answers are right ..?
and im not sure on how to find the x-intercept and the range!? could someone please help me..

Answer by Edwin McCravy(20055) About Me  (Show Source):
You can put this solution on YOUR website!
You have the vertex and y-intercept wrong.

Here is the model to follow:

f(x) = a(x - h)² + k 

has:

vertex: (h,k)

axis of symmetry: x = h

y-intercept: (0,ah²+k)

Domain: all real numbers (-∞, ∞)

Range: 

if a > 0, range is [k, ∞)
if a < 0, range is (-∞, k]


x-intercepts

a(x - h)² + k = 0

    a(x - h)² = -k

     (x - h)² = -k/a
                  ____
        x - h = ±Ö-k/a

                     ____
            x = h ± Ö-k/a

x intercepts are:
                ____
      (x - h - Ö-k/a, 0)

and 

                ____
      (x - h + Ö-k/a, 0)



Now substitute the proper numbers for a, h, k, in all those. 
[Don't let the clashing notation of h and h(x) confuse you, 
they are not the same at all. To avoid confusion use H(x) 
instead of h(x)].

Edwin