SOLUTION: I would sincerely appreciate it if you could please help me solve this grade 11 math equation: 23/(x-1) + 3 - 70/(x^2-4x+3) = 0
I know that when (x^2-4x+3) is factored, it becomes
Question 463912: I would sincerely appreciate it if you could please help me solve this grade 11 math equation: 23/(x-1) + 3 - 70/(x^2-4x+3) = 0
I know that when (x^2-4x+3) is factored, it becomes (x-1)(x-3), and that I need to get rid of the denominator to solve the question, but I'm experiencing some difficulty finishing the question. Answer by lwsshak3(11628) (Show Source):
You can put this solution on YOUR website! 23/(x-1) + 3 - 70/(x^2-4x+3) = 0
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23/(x-1) + 3 - 70/(x^2-4x+3) = 0
23/(x-1) + 3 - 70/(x-1)(x-3) = 0
LCD:(x-1)(x-3)
multiply each term by the LCD, getting rid of the fractions.
23(x-3)+3(x-1)(x-3)-70=0
23(x-3)+3(x^2-4x+3)-70=0
23x-69+3x^2-12x+9-70=0
3x^2+11x-130=0
solve by following quadratic formula:
..
..
a=3, b=11, c=-130
x=[-11ħsqrt(11^2-4*3*-130)]/2*3
x=[-11ħsqrt(121+1560)]6
x=[-11ħ√1681]/6
x=[-11ħ41]/6
x=30/6=5
or
x=52/6
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