Question 463347: The area of this rectangle is 45 square units. Find its length (the horizontal side) and the width (the verticle side). Length is x+6, width is x-6
a) Write an equation using the formula and the given information.
45=
b) Solve the equation, giving only the solution(s) that make sense in the problem. The solution for x is_____
c) Use the solution to find the indicated dimensions of the figure.
Length=
Width=
Answer by lwsshak3(11628)   (Show Source):
You can put this solution on YOUR website! The area of this rectangle is 45 square units. Find its length (the horizontal side) and the width (the verticle side). Length is x+6, width is x-6
a) Write an equation using the formula and the given information.
45=
b) Solve the equation, giving only the solution(s) that make sense in the problem. The solution for x is_____
c) Use the solution to find the indicated dimensions of the figure.
Length=
Width=
...
Given:
length=(x+6)
width=(x-6)
Area=45 sq units
..
Equation:
a) Area=length * width=(x+6)(x-6)=(x^2-36) (difference of two squares)
45=x^2-36
x^2=45+36=81
...
Solution:
b)x=±√81=±9
x=9
or
x=-9 (reject, dimension>0)
..
Dimensions:
c) length=x+6=9+6=15 units
width=x-6=9-6=3 units
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