SOLUTION: 2x^2 + 32x -34 = 0

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Question 461844: 2x^2 + 32x -34 = 0
Answer by jim_thompson5910(35256) About Me  (Show Source):
You can put this solution on YOUR website!

2x%5E2%2B32x-34=0 Start with the given equation.


Notice that the quadratic 2x%5E2%2B32x-34 is in the form of Ax%5E2%2BBx%2BC where A=2, B=32, and C=-34


Let's use the quadratic formula to solve for "x":


x+=+%28-B+%2B-+sqrt%28+B%5E2-4AC+%29%29%2F%282A%29 Start with the quadratic formula


x+=+%28-%2832%29+%2B-+sqrt%28+%2832%29%5E2-4%282%29%28-34%29+%29%29%2F%282%282%29%29 Plug in A=2, B=32, and C=-34


x+=+%28-32+%2B-+sqrt%28+1024-4%282%29%28-34%29+%29%29%2F%282%282%29%29 Square 32 to get 1024.


x+=+%28-32+%2B-+sqrt%28+1024--272+%29%29%2F%282%282%29%29 Multiply 4%282%29%28-34%29 to get -272


x+=+%28-32+%2B-+sqrt%28+1024%2B272+%29%29%2F%282%282%29%29 Rewrite sqrt%281024--272%29 as sqrt%281024%2B272%29


x+=+%28-32+%2B-+sqrt%28+1296+%29%29%2F%282%282%29%29 Add 1024 to 272 to get 1296


x+=+%28-32+%2B-+sqrt%28+1296+%29%29%2F%284%29 Multiply 2 and 2 to get 4.


x+=+%28-32+%2B-+36%29%2F%284%29 Take the square root of 1296 to get 36.


x+=+%28-32+%2B+36%29%2F%284%29 or x+=+%28-32+-+36%29%2F%284%29 Break up the expression.


x+=+%284%29%2F%284%29 or x+=++%28-68%29%2F%284%29 Combine like terms.


x+=+1 or x+=+-17 Simplify.


So the solutions are x+=+1 or x+=+-17