SOLUTION: Tickets sold = -0.2x^2+12x+11
x=1 is the day tickets go on sale. Use the quadratic equation to determine the last day tickets will be sold. I replaced x with 1 in the equation abo
Question 460257: Tickets sold = -0.2x^2+12x+11
x=1 is the day tickets go on sale. Use the quadratic equation to determine the last day tickets will be sold. I replaced x with 1 in the equation above to determine 22.8 tickets were sold on day one, but I'm not sure that is correct. How do I find out the last day tickets were sold? Can you show the work so I can understand how to find the answers? Thanks so much. =) Answer by ankor@dixie-net.com(22740) (Show Source):
You can put this solution on YOUR website! Tickets sold = -0.2x^2+12x+11
x=1 is the day tickets go on sale.
Use the quadratic equation to determine the last day tickets will be sold.
I replaced x with 1 in the equation above to determine 22.8 tickets were sold
on day one, but I'm not sure that is correct.
:
That is correct, but since you can't have a fraction of ticket is would be 23 ticket on day 1
:
How do I find out the last day tickets were sold?
:
That would be when the tickets sold = 0, this is quadratic equation that will
peak and then return thru 0
:
-0.2x^2 + 12x + 11 = 0
you will have to use the quadratic formula to find x
In this equation; a=-.2, b=12, c=11
:
Two solutions
x =
x = -.825, obviously this is not our solution
and
x =
x = +60.825 ~ 61 days for 0 tickets to be sold
:
You can substitute 60.825 for x in the original equation and prove it to yourself
:
Did this make sense to you?
