SOLUTION: The area of the front cover of a daily journal is 273cm squared, and the length is 8cm greater than the width. What are the dimensions of the cover?

Algebra ->  Quadratic Equations and Parabolas  -> Quadratic Equations Lessons  -> Quadratic Equation Lesson -> SOLUTION: The area of the front cover of a daily journal is 273cm squared, and the length is 8cm greater than the width. What are the dimensions of the cover?      Log On


   

Question 459845: The area of the front cover of a daily journal is 273cm squared, and the length is 8cm greater than the width. What are the dimensions of the cover?
Answer by emargo19(101) About Me  (Show Source):
You can put this solution on YOUR website!
Let the width be x
So the length be x+8
x%28x%2B8%29=273
x%5E2%2B8x-273=0
Lets use the quadratic formula
x=%28-b%2B-sqrt%28b%5E2-4ac%29%29%2F2a
x+=+%28-8+%2B-+sqrt%28+8%5E2-4%2A1%2A-273+%29%29%2F%282%2A1%29+
x+=+%28-8+%2B-+sqrt%281156%29%29%2F2
x+=+%28-8+%2B34%29%2F%282%29+ x+=+%28-8+-34%29%2F%282%29+
x+=+%2826%29%2F%282%29+ x+=+%28-42%29%2F%282%29+
x+=+13+ x+=+-21+
The width is 13cm
The length=-21cm