SOLUTION: Given that p and q are the roots of the quadratic equation 2x^2+2px=q^2,if p-q=6 find the value of pq,thanks~~

Algebra ->  Quadratic Equations and Parabolas  -> Quadratic Equations Lessons  -> Quadratic Equation Lesson -> SOLUTION: Given that p and q are the roots of the quadratic equation 2x^2+2px=q^2,if p-q=6 find the value of pq,thanks~~      Log On


   



Question 458365: Given that p and q are the roots of the quadratic equation 2x^2+2px=q^2,if p-q=6 find the value of pq,thanks~~
Found 2 solutions by robertb, josmiceli:
Answer by robertb(5830) About Me  (Show Source):
You can put this solution on YOUR website!
2x%5E2+%2B+2px+=+q%5E2 is equivalent to x%5E2+%2B+px+-+q%5E2%2F2+=+0
==> The sum of the roots are p + q = -p, or 2p = q.
Now p - q = 6 ==> p - 2p = 6, or p = -6.
==> q = 2*-6 = -12, so that pq = -6*-12 = 72.

Answer by josmiceli(19441) About Me  (Show Source):
You can put this solution on YOUR website!
+2x%5E2+%2B+2px+=+q%5E2+
+x%5E2+%2B+px+-+%281%2F2%29%2Aq%5E2+=+0+
The roots are p, and q
+%28+x+-+p+%29%2A%28+x+-+q+%29+=+x%5E2+-+%28p+%2B+q%29%2Ax+%2B+p%2Aq+
++x%5E2+-+%28p+%2B+q%29%2Ax+%2B+p%2Aq+=++x%5E2+%2B+px+-+%281%2F2%29%2Aq%5E2+
+p+=+-+%28p+%2B+q%29+
+-%281%2F2%29%2Aq%5E2+=+p%2Aq+