SOLUTION: find the vertex, line of symmetry, and maximum or minimum value of the quadratic function: f(x)= -2x^2 + 2x + 10
Algebra
->
Quadratic Equations and Parabolas
->
Quadratic Equations Lessons
->
Quadratic Equation Lesson
-> SOLUTION: find the vertex, line of symmetry, and maximum or minimum value of the quadratic function: f(x)= -2x^2 + 2x + 10
Log On
Quadratics: solvers
Quadratics
Practice!
Practice
Answers archive
Answers
Lessons
Lessons
Word Problems
Word
In Depth
In
Click here to see ALL problems on Quadratic Equations
Question 458254
:
find the vertex, line of symmetry, and maximum or minimum value of the quadratic function: f(x)= -2x^2 + 2x + 10
Answer by
solver91311(24713)
(
Show Source
):
You can
put this solution on YOUR website!
Given the quadratic function
The
-coordinate of the vertex is:
The
-coordinate of the vertex is:
The axis of symmetry is
The lead coefficient is negative, hence the parabola opens downward, hence the vertex is a maximum, and the maximum value is the value of the function (read
-coordinate) at the vertex.
John
My calculator said it, I believe it, that settles it