SOLUTION: Please help me solve the problem : The product of two numbers is 90. One number is 3 more than twice the other number. Model these numbers with a quadratic equation. Solve the

Algebra ->  Quadratic Equations and Parabolas  -> Quadratic Equations Lessons  -> Quadratic Equation Lesson -> SOLUTION: Please help me solve the problem : The product of two numbers is 90. One number is 3 more than twice the other number. Model these numbers with a quadratic equation. Solve the      Log On


   

Question 457641: Please help me solve the problem :
The product of two numbers is 90.
One number is 3 more than twice the other number.
Model these numbers with a quadratic equation.
Solve the equation by factoring and using the Zero-Product Property.
Answer by oberobic(2304) About Me  (Show Source):
You can put this solution on YOUR website!
Let's make the two numbers x and y.
x+%2A+y+=+90
.
Let's say x is 3 more than y.
x+=+y+%2B+3
or
x+-+3+=+y
Either way you prefer.
.
Substituting the value of y.
x+%2A+%28x-3%29+=+90
.
Multiply through
x%5E2+-3x+=+90
.
Subtract 90 from both sides.
x%5E2+-3x+-90+=+0
.
Done.